Find the zeroes of the polynomial 4x2 – 9 and verify the relation between the zeros and its coefficients.
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Answer:
the zeroes are 3/2 and (-3/2)
Step-by-step explanation:
4x^2-9
=(2x)^2-3^2
=(2x+3)(2x-3)
therefore,
(2x+3)=0 or (2x-3)=0
=>x=(-3/2). =>x=3/2
now,
3/2+(-3/2)=3-3/2
=0
=-0/4
=-b/a
3/2×(-3/2)=-9/4
=c/a
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