Question

Find the zeroes of the polynomial 5t^2+12t+7 and verify the relationship between its zeroes and the coefficient

Answer 1

Answer:

Step-by-step explanation:

5t²+12t+7

5t²+(5t+7t)+7

5t²+5t+7t+7

5t(t+1)+7(t+1)

(5t+7)(t+1)

t=-7/5 , -1

Relation between zeros are

Sum of zeros= -b/a=-(12)/5=-12/5

-7/5-1=-7-5/5=-12/5

Product of zero=c/a=7/5

-7/5 X -1=7/5

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Answer 2

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