Find the zeroes of the polynomial : 5x(x+2)(x-2)=0
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4√3 x2+5x-2√3=0
=> 4√3x2+8x-3x-2√3=0
=> 4x(√3x+2)-√3(√3x+2)=0
=> (4x-√3)=0 or √3x+2=0
=> x= √3/4 or x= -2/√3
=> 4√3x2+8x-3x-2√3=0
=> 4x(√3x+2)-√3(√3x+2)=0
=> (4x-√3)=0 or √3x+2=0
=> x= √3/4 or x= -2/√3
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