Question

Find the Zeroes of the Polynomial 5x² + 12x+7 and verify the relations between zeroes and the co-efficients of the polynomial. ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

5x² + 12x+7 =0

5x²+5x+7x+7 =0

5x(x+1)+7(x+1) = 0

(x+1)(5x+7) = 0

x = -1, x = -7/5

$\alpha = - 1 \: \: \: \: \beta = - \frac{7}{5}$

sum of zeroes = -b/a

α +β = -12/5

-1-7/5 = -12/5

-12/5 = -12/5

product of zeroes = c/a

αβ = 7/5

-1×-7/5 = 7/5

7/5 = 7/5

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