find the zeroes of the polynomial 5x2-20
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Answered by
3
Answer:
Step-by-step explanation:
5x²-20=0
5(x²-4)=0
5(x+2)(x-2)=0 (:[A-B][A+B]=A²-B²]
if x+2=0
x=-2
if x-2=0
x=2
zeroes are 2 and -2 ANS
Answered by
1
=>5x²-20=0
=>5x²=20
=>x²=4
=>x=√4
=>x=±2
Hence the zeroes are 2,-2.
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