Find the zeroes of the polynomial 6*x square -x-2
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6x^2 - x - 2 = 0
6x^2 + 3x - 4x - 2 = 0
3x ( x + 1 ) - 2 ( x + 1 ) = 0
( x + 1 )( 3x - 2 ) = 0
( x + 1 ) = 0. ( 3x - 2 ) = 0
x = - 1. x = 2/3
6x^2 + 3x - 4x - 2 = 0
3x ( x + 1 ) - 2 ( x + 1 ) = 0
( x + 1 )( 3x - 2 ) = 0
( x + 1 ) = 0. ( 3x - 2 ) = 0
x = - 1. x = 2/3
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