Math, asked by Charlie29, 1 year ago

Find the zeroes of the polynomial 6*x square -x-2
6x  {}^{2}  - x - 2

Answers

Answered by Thatsomeone
1
6x^2 - x - 2 = 0

6x^2 + 3x - 4x - 2 = 0

3x ( x + 1 ) - 2 ( x + 1 ) = 0

( x + 1 )( 3x - 2 ) = 0

( x + 1 ) = 0. ( 3x - 2 ) = 0

x = - 1. x = 2/3
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