Find the zeroes of the polynomial 6x^2-3-7x and verify
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Answer:
3/2,1/3
Step-by-step explanation:
p(x)=6x^2-7x-3=0
=6x^2-2x-9x-3=0
=2x(3x-1)-3(3x-1)=0
=(2x-3)(3x-1) =0
= 2x-3=0 , 3x-1=0
=2x=3. ,3x=1
= x=3/2. , x=1/3
Therefore, the zeroes of the polynomial is 3/2,1/3
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