Question

Find the zeroes of the polynomial 6x2+ x -
12and verify the relation between the coefficients and the zeroes of the polynomial.

Answer 1

Answer:

Step-by-step explanation:

6x2+ x - 12

6x2+9x-8x-12

(3x-4)(2x+3)

Now,

3x-4=0         or 2x+3=0

x=4/3            or x=-3/2

let alpha=4/3 and beta=-3/2

4/3+(-3/2)= -1/6  --- 1

4/3*-3/2=-12/6= -2   ---2

Now,

a=6 , b=1, c=-12

alpha+beta= -b/a= -1/6 ---3

alpha*beta= c/a = -12/6= -2  ---4

From 1,2,3,4 we get 1=3 and 2=4

Hence verified