find the zeroes of the polynomial
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Step-by-step explanation:
Let there remaining zeos be a and b. We know that 3 is one of the zero of given polynomial.
a+b+3= -(-1/2)
a+b= 1/2-3
a+b=-5/2.............. equation (1)
a*b*3=-36/2
a*b=-18/3= -6.......... equation (2)
(a+b)^2-4a*b=(a-b)^2
By putting corresponding values....
(-5/2)^2-4*(-6)=(a-b)^2
25/4+24=121/4=(a-b)^2
By taking square roots of both sides.
11/2=(a-b)......,........... equation (3)
By solving eq. 1 and 3 we get
a+b=-5/2
a-b=11/2
a. 3/2 b. -4
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