Question

find the zeroes of the polynomial

Answer 1

Answer:

Step-by-step explanation:

Let there remaining zeos be a and b. We know that 3 is one of the zero of given polynomial.

a+b+3= -(-1/2)

a+b= 1/2-3

a+b=-5/2.............. equation (1)

a*b*3=-36/2

a*b=-18/3= -6.......... equation (2)

(a+b)^2-4a*b=(a-b)^2

By putting corresponding values....

(-5/2)^2-4*(-6)=(a-b)^2

25/4+24=121/4=(a-b)^2

By taking square roots of both sides.

11/2=(a-b)......,........... equation (3)

By solving eq. 1 and 3 we get

a+b=-5/2

a-b=11/2

a. 3/2 b. -4