Question

Find the zeroes of the polynomial: 8x2 – 2x – 3.

Answer 1

Answer:

(4x-3)(2x+1)

Step-by-step explanation:

8x²-2x-3=0

8x²-6x+4x-3=0

2x(4x-3)+1(4x-3)=0

(4x-3)(2x+1)

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Answer 2

$\begin{gathered}{\Huge{\textsf{\textbf{\underline{\underline{\purple{Answer:}}}}}}}\end{gathered}$

=>8x²-2x-3=0

=> 8x²-6x+4x-3-0

=> 2x(4x-3)+1(4x-3)=0

=> (4x-3)(2x+1)

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