Question

Find the zeroes of the polynomial 9 x∧ 2 + 6 x + 1

Answer 1

Step-by-step explanation:

The expression is equal to the square of 3x+1

Hence answer is -1/3

Answer 2

Step-by-step explanation:

9x² - 6x + 1

= (3x -1)²

∴3x-1 = 0

x = 1/3

∴α = 1/3             ∴β = 1/3

9x² - 6x + 1

ax² + bx + c

∴ a = 9 

  b = -6

  c = 1

αβ =(1/3)(1/3) = 1/9 = a/c

α+β =(1/3)+(1/3) = 2/3= 6/2 = -b/a

Hence verified