Find the zeroes of the polynomial a) x²− 2x b) x² − 9 c) 2x − 9
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Answer:
a) 0
b) -9
c) -9
Step-by-step explanation:
a) p(x) =0
So,p(0)=(0)^2- 2(0)
=0
b)p(x)=0
So,p(0)=(0)^2-9
=(-9)
c)p(x)=0
So,p(0)=2(0)-9
=(-9)
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