Question

find the zeroes of the polynomial and varify the relationship between the zeroes and coefficient.......x²-2x-8​

Answer 1

Answer:Answer. Heya !!! 4 and -2 are the two zeroes of the polynomial X²-2X-8. ... Sum of zeroes = Alpha + Beta = 4 + (-2) = 4-2 = 2/1 = Coefficient of X/Coefficient of X².

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Answer 2

Answer:

Step-by-step explanation:

$P(x)=x^{2} -2x-8$

Let p(x) = 0

Then,

$x^{2} -2x-8=0$

$x^{2} -4x+2x-8=0$    [ on factorizing ]

$x(x-4)+2(x-4)=0$

$(x-4) (x+2)=0$

$x-4=0 and x+2=0$

∴ x = 4 and x = -2

 so,α=4 and β= -2

$x^{2} -2x-8=0$

It is in the form of  $ax^{2} + bx+c=0$ where a=1, b= -2, c= -8

We know that,

α+β = -b/a        and         αβ = c/a

4-2 = -(-2)/1       and        4(-2) = -8/1

2 =2                  and          -8 = -8

               Hence Verified.

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