find the zeroes of the polynomial and verify the relationship between the zeros and their Coefficient x square - 7 x + 12
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Given, polynomial is x² - 7x + 12.
Now, we have to find the zeros of the above polynomial by quadratic formula or by splitting the middle term.
By Splitting the middle term.
⇒ x² - 7x + 12 = 0
The above equation is in the form ax² + bx + c = 0.
Where, a = 1, b = -7 and c = 12
⇒ x² - 3x - 4x + 12 = 0
⇒ x(x - 3) -4(x - 3) = 0
⇒ (x - 4) (x - 3) = 0
On comparing we get,
⇒ x = 4, 3
Therefore,
Zeros are 4 and 3.
Verification:
Sum of zeros = -b/a
⇒ 4 + 3 = -(-7)/1
⇒ 7 = 7
Product of zeros = c/a
⇒ 4 × 3 = 12/1
⇒ 12 = 12
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