find the zeroes of the polynomial and verify the relationship between zeroes and coifficient x^2- root 2 x- 3/2
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Solution :--
——»› Quadratic polynomial ‹«——
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If the coefficient of x^2 is not equal to the 1 then the change the sign of found factors and divide by Coefficient of x^2
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Let's see
We find the factors are. ,
This is a relationship between zeroes and coifficient
———»› thanks for the question bro ❤️✍️✌️
Answered by
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Step-by-step explanation:
Given -
- p(x) = x² - √2x - 3/2
To Find -
- Zeroes of the polynomial
Now,
→ x² - √2x - 3/2 = 0
→ 2x² - 2√2x - 3/2 = 0
→ 2x² - 2√2x - 3 = 0
Now, Factorising this, we get :
By Quadratic formula :
- x = -b ± √b² - 4ac/2a
→ -(-2√2) ± √(-2√2)² - 4×2×-3/2(2)
→ 2√2 ± √8 + 24/4
→ 2√2 ± √32/4
→ 2√2 ± 4√2/4
Zeroes are -
→ x = 2√2 + 4√2/4
→ 6√2/4
- → 3√2/2
And
→ x = 2√2 - 4√2/4
→ -2√2/4
- → -√2/2
Verification :-
As we know that :-
- α + β = -b/a
→ 3√2/2 + (-√2/2) = -(-2√2)/2
→ 3√2/2 - √2/2 = 2√2/2
→ 3√2 - √2/2 = 2√2/2
→ 2√2/2 = √2
→ √2 = √2
LHS = RHS
And
- αβ = c/a
→ 3√2/2 × -√2/2 = -3/2
→ -6/4 = -3/2
→ -3/2 = -3/2
LHS = RHS
Hence,
Verified..
Formula Used :-
☞ Quadratic formula :-
- x = -b ± √b² - 4ac/2a
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