Math, asked by ajaybatham9, 10 months ago

find the zeroes of the polynomial and verify the relationship between zeroes and coifficient​ x^2- root 2 x- 3/2​

Answers

Answered by arunyadav1973
0

Solution :--

——»› Quadratic polynomial ‹«——

 {x}^{2}  -  \sqrt{2} x -  \frac{3}{2}  = 0 \\

  • ————-—————————

 {x}^{2}  -   \sqrt{2} x -  \frac{3}{2}  = 0 \\ multiplying \: by \: 2 \: on \: both \: the \: side \\ 2 {x}^{2} - 2 \sqrt{2} x - 3 = 0 \\ by \: facto risation \: method \\  \\ 2 {x}^{2}  - 3 \sqrt{2} x +  \sqrt{2} x - 3 = 0 \\ (2 {x}^{2}  - 3 \sqrt{2} x)( \sqrt{2} x - 3) = 0 \\  \sqrt{2}x( \sqrt{2} x - 3) 1( \sqrt{2}  x - 3) = 0 \\ ( \sqrt{2}x  - 3)( \sqrt{2} x + 1) = 0 \\ ( \sqrt{2}x  - 3) = 0 \:  \:  \: or \:  \:  \: ( \sqrt{2} x + 1) = 0 \\  \sqrt{2} x = 3 \:  \:  \: or \:  \:  \:  \sqrt{2} x =  - 1 \\ x =  \frac{3}{ \sqrt{2} }  \:  \:  \:  \:  \: or \:  \:  \:  \:  \: x =   \frac{ - 1}{ \sqrt{2} }

If the coefficient of x^2 is not equal to the 1 then the change the sign of found factors and divide by Coefficient of x^2

——————» «——————

Let's see

We find the factors are. ,

 - 3 \sqrt{2} ,  \sqrt{2}  \\ change \: the \: sign \\3 \sqrt{2},      - \sqrt{2}  \\ now \: devide \: by \: coefficient \: of \:  {x}^{2}  \\ i.e. \:  \:  \: 2 \\  \frac{3 \sqrt{2} }{2} ,  \:   \frac{ -  \sqrt{2} }{2}  \\  \frac{3}{ \sqrt{2} } ,  \frac{ - 1}{ \sqrt{2} }

This is a relationship between zeroes and coifficient

» thanks for the question bro ❤️✍️✌️

Answered by TrickYwriTer
2

Step-by-step explanation:

Given -

  • p(x) = x² - √2x - 3/2

To Find -

  • Zeroes of the polynomial

Now,

→ x² - √2x - 3/2 = 0

→ 2x² - 2√2x - 3/2 = 0

→ 2x² - 2√2x - 3 = 0

Now, Factorising this, we get :

By Quadratic formula :

  • x = -b ± √b² - 4ac/2a

→ -(-22) ± √(-22)² - 4×2×-3/2(2)

→ 2√2 ± √8 + 24/4

→ 2√2 ± √32/4

→ 2√2 ± 4√2/4

Zeroes are -

→ x = 2√2 + 4√2/4

→ 6√2/4

  • → 3√2/2

And

→ x = 2√2 - 4√2/4

→ -2√2/4

  • → -√2/2

Verification :-

As we know that :-

  • α + β = -b/a

→ 3√2/2 + (-√2/2) = -(-2√2)/2

→ 3√2/2 - √2/2 = 2√2/2

→ 3√2 - √2/2 = 2√2/2

→ 2√2/2 = √2

→ √2 = √2

LHS = RHS

And

  • αβ = c/a

→ 3√2/2 × -√2/2 = -3/2

→ -6/4 = -3/2

→ -3/2 = -3/2

LHS = RHS

Hence,

Verified..

Formula Used :-

☞ Quadratic formula :-

  • x = -b ± √b² - 4ac/2a

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