Question

find the zeroes of the polynomial and verify the relationship between zeroes and coefficient ,

x² - 8x+12​

Answer 1

Answer:

x= 2 ,6

Step-by-step explanation:

The first term is, x^2 its coefficient is 1 .

The middle term is, -8x its coefficient is -8 .

The last term, "the constant", is +12

Step-1 : Multiply the coefficient of the first term by the constant 1 * 12 = 12

Step-2 : Find two factors of 12 whose sum equals the coefficient of the middle term, which is -8 .

-6 + -2 = -8

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and -2

x2 - 6x - 2x - 12

Step-4 : Add up the first 2 terms, pulling out like factors :

x * (x-6)

Add up the last 2 terms, pulling out common factors :

2 * (x-6)

Step-5 : Add up the four terms of step 4 :

(x-2) * (x-6)

Which is the desired factorization

x= 2 or x= 6.