Question

find the zeroes of the polynomial and verify the relationship between the zeroes and the coefficients
${6x}^{2} - 3 - 7x$
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Answer 1

6x^2 - 7x -3

=6x^2 - 9x + 2x -3

=3x(2x - 3) + 1(2x-3)

=(3x+1)(2x-3)

so, x = -1/3 , 3/2

1) sum of zeroes = 3/2 - 1/3 = 7/6 = co-efficient of x / co-efficient of x^2

2)multiple of zeroes  = 3/2 * -1/3 = -1/2 = constant term / co-efficient of x^2