Question

Find the zeroes of the polynomial and verify the relation between the zeroes and coefficients of the polynomial -
p(x) = x^2 +7x + 12 ​

Answer 1

Step-by-step explanation:

here is your answer,

The polynomial is x²+7x+12

a=1,b=7,c=12

Factors of x²+7x+12

=x²+4x+3x+12

=x(x+4)+3(x+4)

=(x+4)(x+3)

Zeroes of the polynomial

x²+7x+12 =0

(x+4)(x+3)=0

x= -4,-3

ZEROES = -4, -3

SUM OF ROOTS = -4-3=-b/a=-7/1

=> -7=-7

PRODUCT OF ROOTS= -4*-3=c/a

=> 12=12

hope it help u ✔

@ansika .

Answer 2

Step-by-step explanation:

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♡ ↪☛ ...ANSWER

Given,

x^2+7x+12

zeros

x ^2 +7x+12=0

(x+3)(x+4)=0

x=−3,−4

verification,

sum of roots =− a/b

=− 1/7

=−7

product of roots = a/c

= 1/12

=12

Hence proved.

♡

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