Math, asked by sivamrithas286smf, 7 months ago

Find the zeroes of the polynomial and verify the relation between the zeroes and coefficient. x²-7x-8

Answers

Answered by shashiawasthi069
2

Step-by-step explanation:

x²-7x-8

x^2-(8-1)x-8

x^2 -8x+x-8

x(x-8)+1(x-8)

(x+1)(x-8)

zeroes are a = -1 ,B= 8

relation between the zeroes and coefficient.

a= 1 b= -7 c=-8

sum of zeros = -b/a

a+B = -(-7)/1

-1+8 = 7

7 = 7

product of zeros = c/a

aB = -8/1

-1×8 = -8

-8 = -8

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