Find the zeroes of the polynomial ax square -5 and verify the relainship between zeroes and coefficients
Answers
Answered by
3
ax^2 - 5 =0
(ax -5) (ax+5)
ax=5 ax=-5
x=5/a x= -5/a
-(coefficient of x) /( coefficient of x^2)= -5/a
(ax -5) (ax+5)
ax=5 ax=-5
x=5/a x= -5/a
-(coefficient of x) /( coefficient of x^2)= -5/a
sapanaojha:
I am also studying in std 10
Similar questions