Question

Find the zeroes of the polynomial f(x) = √3x

2 + 10x + 7√3 and verify the relation between the zeroes
and its coefficient.

Answer 1

Step-by-step explanation:

a=√3,b=10,c=7√3

X=-b±√b²-4ac/2a

X=-10±√10²-4×√3×7√3/2×√3

X=-10±√100-4×21/2√3

X=-10±√100-84/2√3

X=-10±√16/2√3

X=-10±4/2√3

X=-10+4/2√3 ,X=-10-4/2√3

X=-6/2√3 ,X=-14/2√3

X=-3/√3 ,X=-7/√3

X=-√3,-7/√3

alpha=-√3,beta=-7/√3

alpha + beta=-√3-7/√3

=-3-7/√3

=-10/√3

-b/a=-10/√3

there fore alpha+ beta= -b/a

alpha× beta=-√3×-7/√3

=7

c/a=7√3/√3

=7

there fore alpha× beta= c/a