Find the zeroes of the polynomial f(x)=√3x^2+10x+7√3, verify the relationship between the zeroes and coefficients.
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Answer:
zeros are -√3 and -7/√3
Step-by-step explanation:
f(x) = √3x² + 10x + 7√3
= √3x² + 7x + 3x + 7√3
= x(√3x + 7).√3(√3x + 7)
(x + √3)(√3x + 7)
x = -√3 and √3x = -7
x = -√3 and -7/√3
verification
α + β = -b/a
-√3 + (-7√3) = -10/√3
(-3 - 7)/√3 = -10/√3
-10/√3 = -10/√3
αβ = c/a
(-√3) × (-7/√3) = 7√3/√3
7√3/√3 = 7√3/√3
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