Question

Find the zeroes of the polynomial f(x) = (√3x² - 8x + 4√3 and
verify the relationship between the zeroes and its
coefficients.
ANSWER FAST TO BECOME BRAINLIEST​

Answer 1

Answer:

f(x)=√3x^2 -8x+4√3=0

√3x^2-6x-2x+4√3=0

√3x(x-2√3) -2(x-2√3) =0

(√3x-2) (x-2√3)=0

x=2/√3,2√3

Step-by-step explanation:

Verification

Sum of zeroes =-b/a

2/√3+2√3

=8/√3. (by taking LCM)

Product of zeroes=c/a

2/√3×2√3

=4=4√3/√3=c/a

H.V

Answer 2

Step-by-step explanation:

√3x²-6x-2x+4√3=0

√3x(x-2√3) -2(x-2√3)=0

either (√3x-2) or (x-2√3) = 0

(√3x-2)=0 (x-2√3) =0

x=2/√3 or x= 2√3.

VERIFICATION :-

SUM OF ZEROES = -b/a = -(-8/√3)= 8/√3

2/√3 + 2√3 = 2+√3(2√3)/√3 = 8/√3

PRODUCT OF ZEROES = c/a = 4√3/√3 = 4

2/√3*2√3 = 4

hence verified ..