find the zeroes of the polynomial f(x)= 4√3x^2+5x-2√3 , and show that : sum of zeroes = -5/4√3
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f(x) = 4√3x2 + 5x ‒ 2√3
To find the zeros of the quadratic polynomial,
put f(x) = 0 4√3x2 + 5x ‒ 2√3 = 0 4√3 x2 + 8x – 3x – 2√3 = 0 4x (√3 x + 2) – √3 (√3 x + 2) = 0 (4x – √3) (√3 x + 2) = 0
Either (√3 x + 2) = 0 or (4x – √3) = 0 x = -2/√3 or x = √3/4
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