Question

Find the zeroes of the polynomial f(x) = x^3x3 - 5x^2x2 - 2x +24, if it is given that the product of its two zeroes is 12.​

Answer 1

Step-by-step explanation:

x

3

−5x

2

−2x+24=0

(x+2)

x+2

x

3

−5x

2

−2x+24

(x+2)(x

2

−7x+12)

(x+2)(x

2

−4x−3x−12)

(x+2)(x(x−4)−3(x−4))

(x+2)(x−4)(x−3)

x=−2,3,4

Given, products of 2 zeros is 12⇒(3×4)

Therefore the required solution is 3 and 4.