Question

Find the zeroes of the polynomial f(x) = x³ - 12x² + 47x - 60 , if it is given that sum of its two zeroes is 9. Please answer this.

Answer 1

Answer:

4,5,10

Step-by-step explanation:

x³-12x²+47x-60

α+β+γ=-(-12)/1=12

9+γ=12

y=12-9=3

αβγ=-(-60)/1=60

3αβ=60

αβ=60/3=20

α+β=9

α+αβ/α=9

α+20/α=9

α²-9α+20=0

α²-5α-4α+20=0

α(α-5)-4(α-5)=0

(α-5)(α-4)=0

α=5,THEN β=20/5=4

SO THE ZEROS ARE

4,5,10