Math, asked by diya3113, 8 months ago

Find the zeroes of the polynomial

g(x) =7 under root 2x^2-10x-4underroot 2



helpp guyezz!!​

Answers

Answered by akshitagrawal372
4

Answer:

( x - √2 ) ( 7√2x + 4 )

Step-by-step explanation:

7√2x² - 10x - 4√2

7√2x² - ( 14 - 4 ) x - 4√2

7√2x²- 14x + 4x - 4√2

7√2x( x - √2 ) + 4( x - √2 )

( x - √2 ) ( 7√2x + 4 )

Answered by ajay8949
2

7√2x² - 10x - 4√2

7√2x² - 10x - 4√2 7√2x² - 14x + 4x - 4√2

7√2x² - 10x - 4√2 7√2x² - 14x + 4x - 4√2 7√2x ( x - √2 ) + 4 ( x - √2 )

7√2x² - 10x - 4√2 7√2x² - 14x + 4x - 4√2 7√2x ( x - √2 ) + 4 ( x - √2 )(7√2 X + 4 ) (X - √2 )

zeroes of the polynomial :-

7√2 X + 4 = 0

X = -4 /7√2

X - √2 = 0

X = √2

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