find the zeroes of the polynomial (i) p(x)+2x+1 (ii)p(x) =(x+2)(x+3)
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Answer:
( i ) 2x + 1 = 0
2x = -1
x = -1/2
( ii ) ( x + 2 ) ( x + 3 ) = 0
The zero of polynomial ( x + 2 )
( x + 2 ) = 0
x = -2
The zero of polynomial ( x + 3 )
x + 3 = 0
x = -3
Therefore the zero of polynomial p(x) =(x+2)(x+3) is -2 and -3 .
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