find the zeroes of the polynomial if f(x)=2x^3-9x^2+x+12
(find three zeroes)
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The zero of the polynomial is defined as any real value of x, for which the value of the polynomial becomes zero.
A real number k is a zero of a polynomial p(x), if p(k)= 0.
Given,
f(x) = 2x3-9x2+x+12
Let x=-1
f(-1) = 2(-1)^3-9(-1)^2+(-1)+12
f(-1)=0
So - 1 is the zero of the polynomial.
Now by further solving the equation using synthetic division method, (shown in picture)
We get,
2x^2-11x+12=0
Solving the above equation,
2x^2-8x-3x+12=0
2x(x-4)-3(x-4)=0
(2x-3)(x-4)=0
x=3/2 or 4
Therefore,
Zeros of the polynomial
f(x) = 2x3-9x2+x+12 are
x=-1 , 3/2 , 4
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