find the zeroes of the polynomial p(x)= 2x2-8x+6 and verify the relationship between the zeroes and the coefficient
Answers
Answer:
Step-by-step explanation:
Given polynomial is 2x² - 8x + 6.
We have to find the zeros of the above polynomial.
The above equation is in the form ax² + bx + c = 0.
We have to split the middle term in such a way that their sum is b (-8x) and the product is ac (2*6x² = 12x²)
→ 2x² - 8x + 6 = 0
By Splitting the middle term, we get
→ 2x² - 6x - 2x + 6 = 0
→ 2x(x - 3) -2(x - 3) = 0
→ (2x - 2) (x - 3) = 0
On comparing we get,
→ x = 2/2, 3
→ x = 1, 3
Therefore, zeros are 1 and 3.
Now in given polynomial; a = 2, b = -8 and c = 6
Verification
Sum of zeros = -b/a
1 + 3 = -(-8)/2
4 = 4
Product of zeros = c/a
1 × 3 = 6/2
3 = 3
Answer:
Step-by-step explanation:
Given polynomial is 2x² - 8x + 6.
We have to find the zeros of the above polynomial.
The above equation is in the form ax² + bx + c = 0.
We have to split the middle term in such a way that their sum is b (-8x) and the product is ac (2*6x² = 12x²)
→ 2x² - 8x + 6 = 0
By Splitting the middle term, we get
→ 2x² - 6x - 2x + 6 = 0
→ 2x(x - 3) -2(x - 3) = 0
→ (2x - 2) (x - 3) = 0
On comparing we get,
→ x = 2/2, 3
→ x = 1, 3
Therefore, zeros are 1 and 3.
Now in given polynomial; a = 2, b = -8 and c = 6
Verification
Sum of zeros = -b/a
1 + 3 = -(-8)/2
4 = 4
Product of zeros = c/a
1 × 3 = 6/2
3 = 3