Question

Find the zeroes of the polynomial p ( x ) = √3x^2 + 10x + 7√3

Answer 1

√3x²+10x+7√3=0
√3x²+3x+7x+7√3 =0
√3x(x+√3) +7(x+√3)= 0
therefore, (√3x+7) (x+√3)=0
so, X=-7/√3 and -√3


hope it helps you

Answer 2

step 1☺️☺️
multiply √3and 7√3
we got
21

__step 2
find the no . two no such that their product is 21 and sum is 10
we found that it is 7xand 3x
step3

put the value
√3x^2+7x+3x+7√3

x(√3x+7)+√3(√3x+7)

(√3x+7)×(x+√3)

so, √3x+7=0
x=-7/√3
put x+√3=0
x=-√3
so, their zeroes are -7/√3and -√3
if u satisfied please follow me.