Find the zeroes of the polynomial p(x)=√3x^2-11x+6√3
Answers
Answered by
0
√3x^2-9x-2x+6√3. [18=9*2]
√3x(x-3√3)-2(x-3√3)=0
(√3x-2)(x-3√3)=0
x=2/√3 or 3√3
√3x(x-3√3)-2(x-3√3)=0
(√3x-2)(x-3√3)=0
x=2/√3 or 3√3
Similar questions
Social Sciences,
8 months ago
Math,
8 months ago
Math,
1 year ago
English,
1 year ago
Physics,
1 year ago