Find the zeroes of the polynomial p(x)=√3x^2-11x+6√3
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√3x^2-9x-2x+6√3. [18=9*2]
√3x(x-3√3)-2(x-3√3)=0
(√3x-2)(x-3√3)=0
x=2/√3 or 3√3
√3x(x-3√3)-2(x-3√3)=0
(√3x-2)(x-3√3)=0
x=2/√3 or 3√3
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