Question

Find the zeroes of the polynomial

p(x)=3x²-1, x=-1/√3,2/√3​

Answer 1

$3 {x}^{2} = 1. = > {x}^{2} = \frac{1}{3} = > x = \sqrt{ \frac{1}{3} } = > \frac{1}{ \sqrt{3} } .$

mark it as a brainlist answer.

Answer 2

❁❁Solution❁❁

P(x) = 3x² -1  

where , x = -1/√3 and 2/√3  

put x = -1/√3 in P(x)  

P(-1/√3) = 3(-1/√3)² -1  

= 3×1/3 - 1  

= 0  

it means x = -1/√3 is a root of P(x) .

again, put x = 2/√3  

P(2/√3) = 3(2/√3)² -1  

= 3× 4/3 -1  

= 4 -1 = 3