find the zeroes of the polynomial p(x)=4x^2+3x+7
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Answer:
=4x² + 3x + 7
=4x²- 4x + 7x + 7
=4x(x-1) +7(x +1)
=(4x+7 ) (x+1)
4x +7 =0
4x = 7
x =7/4
x + 1 = 0
x = 1
zeroes of the polynomial 4x² + 3x + 7 are 7/4 and 1.
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