Question

find the zeroes of the polynomial p (x) =6x2-3-7x​

Answer 1

Step-by-step explanation:

p(x) = 6x² - 7x - 3

= 6x² -9x +2x -3

= 3x ( 2x-3) -1 (2x+3)

= (2x-3) (3x+1)

2x-3=0 OR 3x+1=0

2x = 3 3x=-1

x=3/2 x = -1/3

so, the zeroes are x= 3/2 and -1/3....

hope it helps...

Answer 2

Answer:

Given,

p(x) = 6x² - 3 - 7x

= 6x² - 7x -3

To find the zeros of the polynomial,

p(x) = 0

or, 6x² - 7x - 3 = 0

or, 6x² - (9 - 2)x - 3 = 0

or, 6x² - 9x + 2x - 3 = 0

or, 3x(2x - 3) + 1(2x - 3) = 0

or, (2x - 3)(3x + 1) = 0

Either Or

2x - 3 = 0 3x + 1 = 0

or, 2x = 3 or, 3x = -1

or, x = 3/2 or, x = -1/3

So, the zeros of the polynomial are 3/2 & -1/3

HOPE IT HELPS YOU✌✌✌✌✌✌