Find the zeroes of the polynomial. p(x)= (x-2)^2-(x+2)^2
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Answered by
2
(x-2)²-(x+2)²
=x²+4-4x-x²-4-4x
=-8x
so,
zeroes of polynomial
-8x=0
x=0
=x²+4-4x-x²-4-4x
=-8x
so,
zeroes of polynomial
-8x=0
x=0
Brijesh111:
wrong answer
Answered by
0
b=√2 is the zeroes of the polynomial
it is wrong
ok
Now it is correct your answer is wrong
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