Question

Find the zeroes of the polynomial:

P(x) = (x-2)^2- (x + 2)^2​

Answer 1

Answer:

p(x)= -8x answer

x=0 i hope

Answer 2

Answer:

$p(x) = 0 \\ now \: in \: rhs \: side \\ {x}^{2} - 4x + 4 - {x}^{2} + 4x + 4 \\ so \: the \: value \: is \\ p(x) = 4 \\ i.e. \: x = 4 \\ p(x) = ( - 32)$

HOPE IT WILL HELP YOU ...

HERE METHORD IS USED BECAUSE OF THERE IS TWO EQUATION IN RHS. ...