Question

Find the zeroes of the polynomial p(x)=(x - 2)2+(x +
​

Answer 1

Given, polynomial is p(x) = (x – 2)2 – (x+ 2)2

For zeroes of polynomial, put p(x) = 0

(x – 2)2 – (x+ 2)2 = 0

(x-2 + x+2)(x-2-x-2) = 0 [using identity, a2-b2 =(a-b)(a + b)] ⇒ (2x)(-4) = 0

Answer 2

Step-by-step explanation:

Given:

p(x) = (x - 2)² - (x + 2)²

To find:

zeroes of the polynomial.

Solution:

We have

p(x) = (x - 2)² - (x + 2)²

Finding a zero of the polynomial, is the same as solving the equation p(x) = 0, we get

(x - 2 + x + 2)(x - 2 - x - 2) = 0

⇒ (2x) (-4) = 0

⇒-8x = 0

⇒x = 0

Hence, 0 is a zero of the polynomial p(x) = (x - 2)² - (x + 2)²