Question

find the zeroes of the polynomial p(x) =x^2 -(√3+1) x+√3​

Answer 1

Step-by-step explanation:

p(x)=x^2-(root3+1)x+root3

x^2-root3x-x+root3

x(x-root3)-1(x-root3)

(x-1)(x-root3)

x=1,root3