Question

find the zeroes of the polynomial p(X)=x^2-(√3+1)X+√3 and verify the relationship between the zeroes of the coefficients​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

(x-root3)(x-1)

Step-by-step explanation:

x^2-(root3+1)x+root3

on factorizing this equation

we get (x-root3)(x-1)

since ,this equation is an identity

(x+a)(x+b)=x^2+(a+b)x+ab

therefore zeroes of this equation is (x-root3)(x-1)

another part

coefficient is the algebraic number wit sign attached with the variable.

ex :23x^2+2x+1

coefficient of x^2is 23 and coefficient of x is 2.

zero is the value which we put in the equation and on putting this value that particular polynomial be equal to zero

ex:

if p(x)=2x+2

on putting the value if x as-2 in p(x) it becomes zero. therefore -2 is zero this particular equation