Find the zeroes of the polynomial p(x)= x^2+x-12
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Hello,
The equation can be solved as,
p(x)= x²+x-12
= x² +4x - 3x -12 = 0
= x(x+4) - 3 (x+4)
= (x-3) (x+4)
= x = 3 and x = -4.
Hence, zeroes are 3 and -4.
#Rehan Ahmad XLX
#Brainly Star
The equation can be solved as,
p(x)= x²+x-12
= x² +4x - 3x -12 = 0
= x(x+4) - 3 (x+4)
= (x-3) (x+4)
= x = 3 and x = -4.
Hence, zeroes are 3 and -4.
#Rehan Ahmad XLX
#Brainly Star
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