Find the zeroes of the polynomial p(x)=x^2-x-12
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- p(X):-x^2-x-12
- -b±✓b^2-4ac/2a
- a=1,b=-1,c=-12
- 1±✓1+48/2
- 1±✓49/2
- 1±7/2
- 1+7/2. 1-7/2
- 8/2. -6/2
- 4,-3
I hope this helps you
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