Question

Find the zeroes of the polynomial p(x)= x^2+x-12 and draw graph

Answer 1

=x^2+x-12
=x^2+4x-3x-12
=x(x+4)-3(x+4)
=(x-3)(x-4)
x=3 x=4

Answer 2

p(x) = x^2 + x - 12
0 = x^2 - 3x + 4x -12
0 = x[x +4] +4[x-3]
0= [x +4] [x-3]
x= -4, x= 3