Question

find the zeroes of the polynomial p(x)=(x+2) (x+3)​

Answer 1

Step-by-step explanation:

P(x) = (x +2 ) ( x + 3) = 0

therefore, x + 2 = 0 / x + 3 = 0

x = -2 /. x = -3.

hence ,

the zeroes of the polynomial are -2 and -3.

Answer 2

Step-by-step explanation:

$p(x) = (x + 2)(x + 3) \\ \: \: \: \: \: \: \: \: \: = x ^{2} + 3x + 2x + 6 \\ \: \: \: \: \: \: \: \: \: = x ^{2} + 5x + 6 \\ \\ for \: zeros - \\ x + 2 = 0 \\ (x = - 2) \\ \\ x + 3 = 0 \\ (x = - 3)$