Question

find the zeroes of the polynomial p(x)=(x-6)(x-5)

Answer 1

Step-by-step explanation:

(x-6)(x-5)=0

=x-6=0 ;x-5=0

x=6 ;x=5

6and 5 are the zeroes of polynomial

Answer 2

Answer:

$\text{x}_{1}$ = 5 and $\text{x}_{2}$ = 6

Step-by-step explanation:

p(x) = (x - 6)(x - 5)

Substitute the value of p(x) as 0, as we don't have value of x as given

⇒ 0 = (x - 6)(x - 5)

Switch the sides

⇒ (x - 6)(x - 5) = 0

Split into possible cases

⇒ x - 6 = 0

   x - 5 = 0

Solve the equations

⇒ x = 6

   x = 5

The final solutions are :

⇒ $\text{x}_{1}$ = 5

   $\text{x}_{2}$ = 6

∴ The zeroes of the polynomial p(x) = (x - 6)(x - 5) are $\text{x}_{1}$ = 5 and $\text{x}_{2}$ = 6