Find the zeroes of the polynomial p(x)=x square-2x-8
Answers
Answered by
3
p(x) = x² - 2x - 8
x² - 2x - 8 = 0
x² + 2x - 4x - 8 = 0
x(x+2) - 4(x+2) = 0
(x+2) (x-4) = 0
=> x + 2 = 0 ; x = -2
=> x - 4 = 0 ; x = +4
therefore, the zeroes of the polynomial are -2 and +4
hope it helps..!
Answered by
4
here is ur answer----------------❤❤❤
f (X)= X2-2X-8 = X2+X (4-2)-8 = X2+4X-2X-8 = X (X+4)-2 (X+4) = (X-2) (X+4) (X-2)= 0 X= 2 (X+4)= 0 X=-4
hope it helps you dear............❤❤
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