find the zeroes of the polynomial p(x) =x(x-2) (x+3)
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Answer:
0, 2, -3
Step-by-step explanation:
p(x)=0 gives x(x-2)(x+3)=0
so x=0 or x-2=0 or x+3=0
so x=0 or x=2 or x= -3
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