Question

Find the zeroes of the polynomial p(x)=x2 -1.

Answer 1

Answer :

= p(x)=${x}^{2}$ -1

• Let p(x) = 0

Then,

=${x}^{2}$ -1 = 0

= ${x}^{2}$ = 1

= x = $\pm$ 1

•°• The zero of the polynomial is 1.

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Answer 2

The zeroes of the polynomial p(x) = x² - 1 are 1 & - 1

Given :

The polynomial p(x) = x² - 1

To find :

The zeroes of the polynomial

Solution :

Step 1 of 2 :

Write down the given polynomial

The given polynomial is

p(x) = x² - 1

Step 2 of 2 :

Find zeroes of the polynomial

For Zeroes of the polynomial we have

p(x) = 0

⇒ x² - 1 = 0

⇒ x² = 1

⇒ x = ± 1

The zeroes of the polynomial p(x) = x² - 1 are 1 & - 1

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