Question

Find the zeroes of the polynomial p(x) = x2 – 2.​

Answer 1

Answer:

P(x)=(x−2)2−(x−2)2

This is in the form of a2−b2

P(x)=(x−2+x+2)(x−2−(x+2))P(x)=2x(x−2−x−2)P(x)=2x(−4)P(x)=0−8x=0x=0

Hence,

x=0 is the zero of the polynomial P(x)