Question

Find the zeroes of the polynomial p(x) = x2

- 2√ x + 2 and verify the relationship

between the zeroes and the coefficients​

Answer 1

Answer:

${x}^{2} - 2 \sqrt{2x} = 0 \: ⇒ { \purple{a{x}^{2} +bx+c⇒}}$

$a=1 \: b= - 2 \sqrt{2}$

$x(x−2 \sqrt{2}) = 0$

${{ \purple{x=0,2 \sqrt{2}}}}$

${ \boxed{ \huge{ \red{∴∝ = 0, \beta = 2 \sqrt{2}}}}}$

${ \purple{∝+β= \frac{ - b}{a}}}$

$∝+β= \frac{ - ( - 2 \sqrt{2}) }{1}$

${ \huge{ \boxed{ \red{∝+β= 2 \sqrt{2} }}}}$

${ \purple{∝×β= \frac{c}{a} }}$

$∝×β= \frac{0}{1}$

${ \huge{ \boxed{ \red{∝×β= 0}}}}$

$0 + 2 \sqrt{2} = 2 \sqrt{2}$

$( - 2 \sqrt{2} \times 0) = 0$

${ \huge{ \boxed{ \red{L.H.S=R.H.S }}}}$

Step-by-step explanation:

Hope this helps you ✌️